H2SO4+2NH3→(NH4)2SO4
Equivalent of NH3=Equivalent of H2SO4
moles of NH3(nNH3)×1=10002×10×2
=4×10−2moles
Moles of nitrogen=4×10−2moles
Weight of Nitrogen=4×10−2×14=56×10−2gm
Percent of nitrogen=weightofthecompound56×10−2×100=156×10−2×100=56