JEE Main 2023 — Chemistry Organic Chemistry

2023integermedium

The mass of ${\mathrm{NH}}_{3}$ produced when $131.8\mathrm{kg}$ of cyclohexane carbaldehyde undergoes Tollen’s test is _____ $\mathrm{kg}$ . (Nearest Integer)

Molar mass of $C=12g/\mathrm{mol}$

$N=14g/\mathrm{mol}$

$O=16g/\mathrm{mol}$

Official previous-year question

Held on 12 Apr 2023 · Verified 6 Jul 2026.

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Solution

$\mathrm{RCHO}+2[\mathrm{Ag}{({\mathrm{NH}}_{3})}_{2}]\mathrm{OH}\rightarrow {\mathrm{RCOONH}}_{4}+2\mathrm{Ag}+3{\mathrm{NH}}_{3}+{H}_{2}O$

The $\mathrm{RCHO}$ is cyclohexane carbaldehyde ( ${C}_{6}{H}_{11}\mathrm{CHO}$ ). The molar mass is $112g$ .

The number of moles of cyclohexane carbaldehyde $=\frac{131.8\times {10}^{3}}{112}=1.176\times {10}^{3}\mathrm{mol}$

$1$ mole of aldehyde produces $3$ moles of ${\mathrm{NH}}_{3}$

$1.176\times {10}^{3}$ mol aldehyde will produce

$=3\times 1.176\times {10}^{3}$ moles of ${\mathrm{NH}}_{3}$

Mass of ${\mathrm{NH}}_{3}$ produced $=3\times 1.176\times {10}^{3}\times 17$

$=59.97\times {10}^{3}g$

$\approx 60\mathrm{kg}$

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Solution

$\mathrm{RCHO}+2[\mathrm{Ag}{({\mathrm{NH}}_{3})}_{2}]\mathrm{OH}\rightarrow {\mathrm{RCOONH}}_{4}+2\mathrm{Ag}+3{\mathrm{NH}}_{3}+{H}_{2}O$

The $\mathrm{RCHO}$ is cyclohexane carbaldehyde ( ${C}_{6}{H}_{11}\mathrm{CHO}$ ). The molar mass is $112g$ .

The number of moles of cyclohexane carbaldehyde $=\frac{131.8\times {10}^{3}}{112}=1.176\times {10}^{3}\mathrm{mol}$

$1$ mole of aldehyde produces $3$ moles of ${\mathrm{NH}}_{3}$

$1.176\times {10}^{3}$ mol aldehyde will produce

$=3\times 1.176\times {10}^{3}$ moles of ${\mathrm{NH}}_{3}$

Mass of ${\mathrm{NH}}_{3}$ produced $=3\times 1.176\times {10}^{3}\times 17$

$=59.97\times {10}^{3}g$

$\approx 60\mathrm{kg}$

JEE Main 2023 — Chemistry Organic Chemistry

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JEE Main 2023 — Chemistry Organic Chemistry

Did you get this right?

Solution

Your note

JEE Main Organic Chemistry in other years

More JEE Main Organic Chemistry questions

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Keep practicing Organic Chemistry