From the given information:
Moles of hydrocarbon =13617×10−3=1.25×10−4 Mole of H2 gas
⇒1×10008.40=n×0.0821×273
⇒n=3.75×10−4
Thus, moles of hydrogen used to hydrogenate double bonds:
=1.25×10−43.75×10−4=3
17mg of a hydrocarbon (M.F. C10H16) takes up 8.40mL of the H2 gas measured at 0∘C and 760mm of Hg. Ozonolysis of the same hydrocarbon yields
CH3−O∣∣C−CH3,H−O∣∣C−H,H−O∣∣C−CH2−CH2−O∣∣C−O∣∣C−H
The number of double bond/s present in the hydrocarbon is
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