How many of the transformation given below would result in aromatic amines? ![JEE Main 2023 Chemistry, Amines — question figure](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/615f0e999476412f48314daf/Chemistry/images/Amines/648b5a70417cc3fb48d682a9/question_1__q_648b5a70417cc3fb48d682a9__cdn-question-pool.getmarks.app__0168daf9-5456-4cdd-bf14-1a947873a4da-9896183_3__f611bb6e27_final_ppt_sync.png)

Products in the given reactions are as follows: 1. Hoffmann bromamide degradation is useful in the production of aniline as it converts the $-{\mathrm{CONH}}_{2}$ functional group into the $-{\mathrm{NH}}_{2}$ group. So, we need to take a starting material that has the $-{\mathrm{CONH}}_{2}$ group and after getting converted into $-{\mathrm{NH}}_{2}$ group, the molecule obtained is aniline. So, in order to obtain aniline as the final product, we require Benzamide as a starting material. So, in this way, we can easily convert Benzamide to Aniline. ![JEE Main 2023 Chemistry, Amines — solution figure 1](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/615f0e999476412f48314daf/Chemistry/images/Amines/648b5a70417cc3fb48d682a9/solution_1__q_648b5a70417cc3fb48d682a9__cdn-question-pool.getmarks.app__3b3bad20-6680-447a-97a4-3f7bd238d279-9896183__c593af6606_final_ppt_sync.png) 2. Gabriel phthalimide synthesis cannot be used to prepare aniline because aryl halides do not give Gabriel phthalimide reaction. ![JEE Main 2023 Chemistry, Amines — solution figure 2](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/615f0e999476412f48314daf/Chemistry/images/Amines/648b5a70417cc3fb48d682a9/solution_2__q_648b5a70417cc3fb48d682a9__cdn-question-pool.getmarks.app__01dc03c0-9049-46a0-9d62-995e7b892caa-image__02bfb49bfd_final_ppt_sync.png) 3. When nitrobenzene is reacted with an active metal like Pd/C and H$_{2}$$_{,}$ it produces aniline. This reaction is also called Nitrobenzene reduction. ![JEE Main 2023 Chemistry, Amines — solution figure 3](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/615f0e999476412f48314daf/Chemistry/images/Amines/648b5a70417cc3fb48d682a9/solution_3__q_648b5a70417cc3fb48d682a9__cdn-question-pool.getmarks.app__da2c02d8-7d00-40bb-97ff-e50f3bea7704-9896183_4__8fa5c944c2_final_ppt_sync.png) 4. When acetanilide is treated with dil. ${H}_{2}{\mathrm{SO}}_{4}$, it produces aniline. Aromatic amines will be formed in $1,3&4$. So, answer is 3.

JEE Main 2023 — Chemistry Organic Chemistry

2023integerhard

How many of the transformation given below would result in aromatic amines?

JEE Main 2023 Chemistry, Amines — question figure

Official previous-year question

Held on 31 Jan 2023 · Verified 6 Jul 2026.

Did you get this right?

Solution

Products in the given reactions are as follows:

Hoffmann bromamide degradation is useful in the production of aniline as it converts the $-{\mathrm{CONH}}_{2}$ functional group into the $-{\mathrm{NH}}_{2}$ group. So, we need to take a starting material that has the $-{\mathrm{CONH}}_{2}$ group and after getting converted into $-{\mathrm{NH}}_{2}$ group, the molecule obtained is aniline. So, in order to obtain aniline as the final product, we require Benzamide as a starting material. So, in this way, we can easily convert Benzamide to Aniline.

JEE Main 2023 Chemistry, Amines — solution figure 1

Gabriel phthalimide synthesis cannot be used to prepare aniline because aryl halides do not give Gabriel phthalimide reaction.

JEE Main 2023 Chemistry, Amines — solution figure 2

When nitrobenzene is reacted with an active metal like Pd/C and H $_{2}$ $_{,}$ it produces aniline. This reaction is also called Nitrobenzene reduction.

JEE Main 2023 Chemistry, Amines — solution figure 3

When acetanilide is treated with dil. ${H}_{2}{\mathrm{SO}}_{4}$ , it produces aniline.

Aromatic amines will be formed in $1,3&4$ .

So, answer is 3.

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2026medium

Given below are two statements: Statement I: $\left(\mathrm{CH}_{3}\right)_{3} \stackrel{\oplus}{\mathrm{C}}$ is more stable than $\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{3}$ as nine hyperconjugation interactions are possible in $\left(\mathrm{CH}_{3}\right)_{3} \stackrel{\oplus}{\mathrm{C}}$. Statement II: $\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{3}$ is less stable than $\left(\mathrm{CH}_{3}\right)_{3} \stackrel{\oplus}{\mathrm{C}}$ as only three hyperconjugation interactions are possible in $\stackrel{\oplus}{\mathrm{C}} \mathrm{H}_{3}$. In the light of the above statements, choose the correct answer from the options given below

2026medium

Which of the following reactions is an example of Wurtz reaction?

2026easy

A hydroxy compound $(\mathrm{X})$ with molar mass $122 \mathrm{~g} \mathrm{~mol}^{-1}$ is acetylated with acetic anhydride, using a large excess of the reagent ensuring complete acetylation of all hydroxyl groups. The product obtained has a molar mass of $290 \mathrm{~g} \mathrm{~mol}^{-1}$. The number of hydroxyl groups present in compound (X) is:

2026medium

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JEE Main 2023 — Chemistry Organic Chemistry

2023integerhard

How many of the transformation given below would result in aromatic amines?

JEE Main 2023 Chemistry, Amines — question figure

Official previous-year question

Held on 31 Jan 2023 · Verified 6 Jul 2026.

Did you get this right?

Solution

Products in the given reactions are as follows:

Hoffmann bromamide degradation is useful in the production of aniline as it converts the $-{\mathrm{CONH}}_{2}$ functional group into the $-{\mathrm{NH}}_{2}$ group. So, we need to take a starting material that has the $-{\mathrm{CONH}}_{2}$ group and after getting converted into $-{\mathrm{NH}}_{2}$ group, the molecule obtained is aniline. So, in order to obtain aniline as the final product, we require Benzamide as a starting material. So, in this way, we can easily convert Benzamide to Aniline.

JEE Main 2023 Chemistry, Amines — solution figure 1

Gabriel phthalimide synthesis cannot be used to prepare aniline because aryl halides do not give Gabriel phthalimide reaction.

JEE Main 2023 Chemistry, Amines — solution figure 2

When nitrobenzene is reacted with an active metal like Pd/C and H $_{2}$ $_{,}$ it produces aniline. This reaction is also called Nitrobenzene reduction.

JEE Main 2023 Chemistry, Amines — solution figure 3

When acetanilide is treated with dil. ${H}_{2}{\mathrm{SO}}_{4}$ , it produces aniline.

Aromatic amines will be formed in $1,3&4$ .

So, answer is 3.

Your note

JEE Main Organic Chemistry in other years

Keep practicing Organic Chemistry

Work through every JEE Main Organic Chemistry PYQ, year by year.

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JEE Main 2023 — Chemistry Organic Chemistry

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Solution

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JEE Main 2023 — Chemistry Organic Chemistry

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Solution

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JEE Main Organic Chemistry in other years

More JEE Main Organic Chemistry questions

Other Chemistry topics for JEE Main

Physical Chemistry

Inorganic Chemistry

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