π=CRT
5.03×10−3=[M.wt×5002.5×1000]×0.083×300
M.wt. =24.752×103gram=24752gram
Molar mass of glycine (NH2CH2COOH)=75g/Mol.
No of glycine unit in protein =7524752=330.02≃330units
2.5g of protein containing only glycine (C2H5NO2) is dissolved in water to make 500mL of solution. The osmotic pressure of this solution at 300K is found to be 5.03×10−3 bar. The total number of glycine units present in the protein is
(Given : R=0.083LbarK−1mol−1)
Held on 28 Jun 2022 · Verified 6 Jul 2026.
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