In Duma's method of estimation of Nitrogen. 0.1840gm of organic compound gave 30mL of nitrogen which is collected at 287K and 758mm of Hg.
Given ;
Aqueous tension at 287K=14mmof Hg.
Hence, actual pressure =(758−14)
=744mm of Hg.
Volume of nitrogen at STP=287×760273×744×30
V=27.935mL
∵22400mL of N2 at STP weighs =28gm.
∴27.94mL of N2 at STP weighs =(2240028×27.94)gm
=0.0349gm
Hence of Nitrogen =(0.18400.0349×100)
=18.97
Round off. Answer =19