JEE Main 2020 — Chemistry Organic Chemistry
Consider the following reactions:
(a)(a)(a) (CH3)3CCH(OH)CH3→conc.H2SO4{(C{H}_{3})}_{3}CCH(OH)C{H}_{3}\overset{conc.{H}_{2}S{O}_{4}}{\rightarrow }(CH3)3CCH(OH)CH3→conc.H2SO4
(b)(b)(b) (CH3)2CHCH(Br)CH3→alc.KOH{(C{H}_{3})}_{2}CHCH(Br)C{H}_{3}\overset{alc.KOH}{\rightarrow }(CH3)2CHCH(Br)CH3→alc.KOH
(c)(c)(c) (CH3)2CHCH(Br)CH3→(CH3)3O⊖K⊕{(C{H}_{3})}_{2}CHCH(Br)C{H}_{3}\overset{{(C{H}_{3})}_{3}{O}^{\ominus }{K}^{\oplus }}{\rightarrow }(CH3)2CHCH(Br)CH3→(CH3)3O⊖K⊕
(d)(d)(d)
Which of the reaction(s) will not produce Saytzeff product?
Held on 7 Jan 2020 · Verified 6 Jul 2026.
(a),(c)(a),(c)(a),(c) and (d)(d)(d)
(d)(d)(d) only
(c)(c)(c) only
(b)(b)(b) and (d)(d)(d)
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We have to know that a Saytzeff product is basically an alkene compound which has undergone many substitution reactions to form the alkene product. From Saytzeff rule, a stable alkene is formed when removal of hydrogen from beta carbon has a low number of hydrogen atoms.
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