C6H5I will not respond to silver nitrate test because C-I bond has a partial double bond character.
JEE Main 2003 — Chemistry Organic Chemistry
Bottles containing C6H5 l and C6H5CH2I lost their original labels. They were labelled A and B for testing A and B were separately taken in test tubes and boiled with NaOH solution. The end solution in each tube was made acidic with dilute HNO3 and then some AgNO3 solution was added. Substance B gave a yellow precipitate. Which one of the following statements is true for this experiment?
Held on 30 Apr 2003 · Verified 6 Jul 2026.
A and C6H5CH2I
B and C6H5I
Addition of HNO3 was unnecessary
A was C6H5I
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
A student has been given a compound " $x$ " of molecular formula- $\mathrm{C}_{6} \mathrm{H}_{7} \mathrm{~N}$. ' $x$ ' is sparingly soluble in water. However, on addition of dilute mineral acid, ' $x$ ' becomes soluble in water. ' $x$ ' when treated with $\mathrm{CHCl}_{3}$ and $\mathrm{KOH}($ alc $)$, ' $y$ ' is produced. ' y ' has a specific unpleasant smell. On treatment with benzenesulphonyl chloride, ' $x$ ' gives a compound ' $z$ ' which is soluble in alkali. The number of different " $H$ " atoms present in ' $z$ ' is:-
Given below are two statements : Statement I: Compound $(X)$, shown below, dissolves in $\mathrm{NaHCO}_{3}$ solution and has two chiral carbon atoms  Statement II: Compound $(\mathrm{Y})$, shown below, has two carbons with $\mathrm{sp}^{3}$ hybridization, one carbon with $\mathrm{sp}^{2}$ and one carbon with sp hybridization  In the light of the above statements, choose the correct answer from the options given below :
$4.7$ g of phenol is heated with Zn to give product X. If this reaction goes to $60\%$ completion then the number of moles of compound X formed will be _______ $\times 10^{-2}$. (Nearest Integer) (Given molar mass in g mol$^{-1}$: H:1, C:12, O:16)
The mass of benzanilide obtained from the benzoylation reaction of 5.8 g of aniline, if yield of product is $82 \%$, is $\_\_\_\_$ g (nearest integer). (Given molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N}: 14, \mathrm{O}: 16$)
Consider the following sequence of reactions.  The percentage of nitrogen in the yellow product (X) formed is _______%. (Nearest Integer) (Given Molar mass in g mol$^{-1}$ H:1, C:12, N:14)
Work through every JEE Main Organic Chemistry PYQ, year by year.