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Consider the nuclear fission, Ne^20→ 2 He^4+C^12. Given that the binding energy/nucleon of Ne^20, He^4andC^12 are 8.03 MeV,7.86 MeV, respectively.…

JEE Main 2019 — Physics Modern Physics

2019mcqmedium

Consider the nuclear fission, Ne20→2He4+C12{\mathrm{Ne}}^{20}\rightarrow 2{\mathrm{He}}^{4}+{C}^{12}Ne20→2He4+C12. Given that the binding energy/nucleon of Ne20,He4{\mathrm{Ne}}^{20},{\mathrm{He}}^{4}Ne20,He4andC12{C}^{12}C12 are 8.03MeV,7.86MeV8.03 \mathrm{MeV},7.86\mathrm{MeV}8.03MeV,7.86MeV, respectively. Identify the correct statement:

Official previous-year question

Held on 10 Jan 2019 · Verified 6 Jul 2026.

Options

  1. A

    Energy of 12.4MeV12.4\mathrm{MeV}12.4MeV will be supplied.

  2. B

    Energy of 9.72MeV9.72\mathrm{MeV}9.72MeV has to be supplied.

  3. C

    Energy of 3.6MeV3.6\mathrm{MeV}3.6MeV will be released.

  4. D

    8.3MeV8.3\mathrm{MeV}8.3MeV energy will be released.

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