Using Einstein's photoelectric equation with stopping potentials:
For first light, hν1=ϕ+eVs1.
For second light with λ2=2λ1 (so ν2=ν1/2): hν1/2=ϕ+eVs2.
From given values: hν1−3.2e=hν1/2−0.7e gives hν1/2=2.5e.
Thus λ1=5ehc=5×1.6×10−196.63×10−34×3×108≈2.5×10−7 m.