The output of the first NAND gate
Y′=A⋅Bˉ
The output of the second NAND gate
Y=(A⋅Bˉ)⋅(A⋅Bˉ)ˉ⇒Y=(A⋅Bˉˉ)+(A⋅Bˉˉ)⇒Y=A⋅B
So, the equivalent circuit will be an AND gate.
AND(A=1,B=1,Y=1)
Identify the gate and match A,B,Y in the bracket to check. JEE Main 2014 Physics, Semiconductors — question figure
JEE Main 2014 — Physics Modern Physics
2014mcqeasy
Identify the gate and match A,B,Y in the bracket to check.
Official previous-year question
Held on 9 Apr 2014 · Verified 6 Jul 2026.
Options
- A
OR(A=1,B=1,Y=0)
- B
XOR(A=0,B=0,Y=0)
- C
NOT(A=1,B=1,Y=1)
- D
AND(A=1,B=1,Y=1)
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