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Surface tension of two liquids (having same densities), T_1 and T_2, are measured using capillary rise method utilizing two tubes with inner radii of…

JEE Main 2026 — Physics Mechanics

2026mcqeasy

Surface tension of two liquids (having same densities), T1T_{1}T1​ and T2T_{2}T2​, are measured using capillary rise method utilizing two tubes with inner radii of r1r_{1}r1​ and r2r_{2}r2​ where r1>r2r_{1}>r_{2}r1​>r2​. The measured liquid heights in these tubes are h1h_{1}h1​ and h2h_{2}h2​ respectively. [Ignore the weight of the liquid about the lowest point of miniscus]. The heights h1h_{1}h1​ and h2h_{2}h2​ and surfaces tensions T1T_{1}T1​ and T2T_{2}T2​ satisfy the relation:

Official previous-year question

Held on 21 Jan 2026 · Verified 6 Jul 2026.

Options

  1. A

    h1>h2 and T1=T2h_{1}>h_{2} \text { and } T_{1}=T_{2}h1​>h2​ and T1​=T2​

  2. B

    h1=h2 and T1=T2h_{1}=h_{2} \text { and } T_{1}=T_{2}h1​=h2​ and T1​=T2​

  3. C

    h1>h2 and T1<T2h_{1} > h_{2} \text { and } T_{1} < T_{2}h1​>h2​ and T1​<T2​

  4. D

    h1<h2 and T1=T2h_{1} < h_{2} \text { and } T_{1}=T_{2}h1​<h2​ and T1​=T2​

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