Let A be the base area of the wooden cube.
A=10 cm×10 cm=100 cm2
Let Δx be the increase in the submerged depth of the cube when the coin is placed on it.
Δx=3.87 cm
The additional volume of water displaced due to the weight of the metal coin is ΔV=A×Δx.
ΔV=100×3.87=387 cm3
By Archimedes' principle, the weight of the metal coin is balanced by the additional buoyant force, which is equal to the weight of the additional water displaced.
mg=ΔVρwg
m=ΔVρw
Substituting the values of ΔV and the density of water ρw=1 g/cm3:
m=387 cm3×1 g/cm3=387 g
Answer: 387