Let the mass of the original solid sphere be M and its radius be R.
Mass of the smaller sphere, m1=8M.
Since the material remains the same, the density is constant. The volume is directly proportional to the mass.
34πr3=81(34πR3)⇒r3=8R3⇒r=2R
Moment of inertia of the smaller sphere about an axis through its centre is:
I1=52m1r2=52(8M)(2R)2=52×8M×4R2=80MR2
Mass of the larger part (which is converted into a disc) is:
m2=M−8M=87M
The radius of the disc is given as 2R. The moment of inertia of a disc about its diameter is:
I2=41m2(radius)2=41(87M)(2R)2=41×87M×4R2=87MR2
The ratio of their moments of inertia is:
I1I2=80MR287MR2=87×80=70
Answer: 70