Using WET
Total energy supplied = gravitational potential energy + spring potential energy + work done by gas
$\begin{aligned}
& \operatorname{Mg} \quad\left(L_1-L_0\right)+\int_{L_0}^{L_1} k^3 d x+n R T \ell n \
& {\left[\frac{L_1 \mathrm{A}}{\mathrm{L}0 \mathrm{~A}}\right]+\mathrm{W}{\mathrm{ext}}=0} \
& \frac{\mathrm{~K}}{4}\left[\mathrm{x}^4\right]_{\mathrm{L}_0}^{\mathrm{L}_1}+\operatorname{Mg}\left(\mathrm{L}_1-\mathrm{L}0\right)+\int{\mathrm{L}_0}^{\mathrm{L}_1} k x^3 d x+n R T \ell n
\end{aligned}$
[L0L1]+Wext=04k( L14−L04)+Mg(L1−L0)+nRTℓn[ L0L1]+Wext=0 Wext=4k( L14−L04)+Mg(L1−L0)+nRTℓn[ L0L1]