Given 9MSD=10VSD mass=8.635 g LC=1MSD−1VSDLC=1MSD−109MSDLC=101MSDLC=0.01 cm Reading of diameter =MSR+LC×VSR =2 cm+(0.01)×(2)=2.02 cm Volume of sphere =34π(2d)3=34π(22.02)3 =4.32 cm3 Density = volume mass =4.328.635=1.998∼2.00 g
The diameter of a sphere is measured using a vernier caliper whose 9 divisions of main scale are equal to 10 divisions of vernier scale. The shortest…
JEE Main 2024 — Physics Mechanics
The diameter of a sphere is measured using a vernier caliper whose 9 divisions of main scale are equal to 10 divisions of vernier scale. The shortest division on the main scale is equal to 1 mm. The main scale reading is 2 cm and second division of vernier scale coincides with a division on main scale. If mass of the sphere is 8.635 g, the density of the sphere is:
Held on 8 Apr 2024 · Verified 6 Jul 2026.
Options
- A
2.0 g/cm3
- B
1.7 g/cm3
- C
2.2 g/cm3
- D
2.5 g/cm3
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