
Case-1 : No friction $\begin{aligned}
& \mathrm{a}=\mathrm{g} \sin \theta \
& \ell=\frac{1}{2}(\mathrm{g} \sin \theta) \mathrm{t}_1^2 \
& \mathrm{t}_1=\sqrt{\frac{2 \ell}{\mathrm{g} \sin \theta}}
\end{aligned}Case−2:Withfriction\begin{aligned}
& \mathrm{a}=\mathrm{g} \sin \theta-\mu \mathrm{g} \cos \theta \
& \ell=\frac{1}{2}(\mathrm{g} \sin \theta-\mu \mathrm{g} \cos \theta) \mathrm{t}_2^2 \
& \sqrt{\frac{2 \ell}{\mathrm{g} \sin \theta-\mu g \cos \theta}}=\mathrm{n} \sqrt{\frac{2 \ell}{\mathrm{g} \sin \theta}} \
& \mu=1-\frac{1}{\mathrm{n}^2}
\end{aligned}$