d=2Rcosθ
∴ Pressure difference across a liquid surface is
ΔP=T(R11+R21)
∵R1=RandR2=R
ΔP=T(R1+R1)
ΔP=R2T
∴ Pressure is more in the concave side hence pressure in water between the plates is lower by R2T
If two glass plates have water between them and are separated by very small distance (see figure), it is very difficult to pull them apart. It is…
JEE Main 2015 — Physics Mechanics
2015mcqmedium
If two glass plates have water between them and are separated by very small distance (see figure), it is very difficult to pull them apart. It is because the water in between forms cylindrical surface on the side that gives rise to lower pressure in the water in comparison to atmosphere. If the radius of the cylindrical surface is R and surface tension of water is T then the pressure in water between the plates is lower by:
Official previous-year question
Held on 10 Apr 2015 · Verified 6 Jul 2026.
Options
- A
RT
- B
4RT
- C
R4T
- D
R2T
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