A ball projected from ground at an angle of 45° just clears a wall in front. If point of projection is 4 ~m from the foot of wall and ball strikes…
JEE Main 2013 — Physics Mechanics
2013mcqmedium
A ball projected from ground at an angle of 45∘ just clears a wall in front. If point of projection is 4m from the foot of wall and ball strikes the ground at a distance of 6m on the other side of the wall, the height of the wall is :
Official previous-year question
Held on 22 Apr 2013 · Verified 6 Jul 2026.
Options
A
4.4m
B
2.4m
C
3.6m
D
1.6m
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Solution
As ball is projected at an angle 45∘ to the horizontal therefore Range =4H or 10=4H⇒H=410=2.5m(∵ Range =4m+6m=10m) Maximum height, H=2gu2sin2θ∴u2=sin2θH×2g=(21)22.5×2×10=100 or, u=100=10ms−1 Height of wall PA =OAtanθ−21u2cos2θg(OA)2=4−21×10×10×n1×0110×16=2.4m
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