Energy = Work done by force (F) ⇒21 m.(50)2=(F)(6)⇒F=2×62500 m For v=100 km/hr21⋅m(100)2=(F)(S) ⇒21 m(100)2=(2×62500 m)S⇒S=2500×2100×100×6×2=24 m
JEE Main 2003 — Physics Mechanics
A car, moving with a speed of 50 km/hr, can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/hr, the minimum stopping distance is
Held on 30 Apr 2003 · Verified 6 Jul 2026.
12 m
18 m
24 m
6 m
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