HCl⟶H++Cl− Strong acid (Complete ionisation) NH4OH⇌NH4++OH− Weak base ΔH=x kJ mol−1 H++OH−⟶H2OΔH=−55.90 kJ mol−1 (from neutralisation of strong acid and strong base) From equation (i), (ii) and (iii) ∴NH4OH+HCl⟶NH4++Cl−+H2OΔH=−51.46 kJ mol−1x+(−55.90)=−51.46x=−51.46+55.90=4.44 kJ mol−1 ∴ Enthalpy of ionisation of NH4OH=4.44 kJ mol−1