JEE Main 2026 — Chemistry Physical Chemistry

2026mcqmedium

Arrange the following resultant mixtures in increasing order of their pH values

A. $10$ mL $0.2$ M Ca(OH) $_2$ + $25$ mL $0.1$ M HCl

B. $10$ mL $0.01$ M H $_2$ SO $_4$ + $10$ mL $0.01$ M Ca(OH) $_2$

C. $10$ mL $0.1$ M H $_2$ SO $_4$ + $10$ mL $0.1$ M KOH

Choose the correct answer from the options given below:

Official previous-year question

Held on 5 Apr 2026 · Verified 6 Jul 2026.

Options

A
$B < C < A$
B
$C < A < B$
C
$C < B < A$
D
$A < C < B$

Did you get this right?

Solution

For mixture A:

Millimoles of OH $^{-}$ = $10 \times 0.2 \times 2 = 4$

Millimoles of H $^{+}$ = $25 \times 0.1 \times 1 = 2.5$

Remaining OH $^{-}$ = $4 - 2.5 = 1.5$ mmol

The solution is basic, so pH $> 7$ .

For mixture B:

Millimoles of H $^{+}$ = $10 \times 0.01 \times 2 = 0.2$

Millimoles of OH $^{-}$ = $10 \times 0.01 \times 2 = 0.2$

The solution is completely neutralized, so pH $= 7$ .

For mixture C:

Millimoles of H $^{+}$ = $10 \times 0.1 \times 2 = 2$

Millimoles of OH $^{-}$ = $10 \times 0.1 \times 1 = 1$

Remaining H $^{+}$ = $2 - 1 = 1$ mmol

The solution is acidic, so pH $< 7$ .

Therefore, the increasing order of pH values is C $<$ B $<$ A.

Answer: $C < B < A$

Your note

JEE Main Physical Chemistry in other years

Physical Chemistry 2025 Physical Chemistry 2024 Physical Chemistry 2023 Physical Chemistry 2022 Physical Chemistry 2021 Physical Chemistry 2020 Physical Chemistry 2019 Physical Chemistry 2018 Physical Chemistry 2017 Physical Chemistry 2016 Physical Chemistry 2015 Physical Chemistry 2014

Keep practicing Physical Chemistry

Work through every JEE Main Physical Chemistry PYQ, year by year.

Browse all Chemistry topics

Solution

For mixture A:

Millimoles of OH $^{-}$ = $10 \times 0.2 \times 2 = 4$

Millimoles of H $^{+}$ = $25 \times 0.1 \times 1 = 2.5$

Remaining OH $^{-}$ = $4 - 2.5 = 1.5$ mmol

The solution is basic, so pH $> 7$ .

For mixture B:

Millimoles of H $^{+}$ = $10 \times 0.01 \times 2 = 0.2$

Millimoles of OH $^{-}$ = $10 \times 0.01 \times 2 = 0.2$

The solution is completely neutralized, so pH $= 7$ .

For mixture C:

Millimoles of H $^{+}$ = $10 \times 0.1 \times 2 = 2$

Millimoles of OH $^{-}$ = $10 \times 0.1 \times 1 = 1$

Remaining H $^{+}$ = $2 - 1 = 1$ mmol

The solution is acidic, so pH $< 7$ .

Therefore, the increasing order of pH values is C $<$ B $<$ A.

Answer: $C < B < A$

JEE Main 2026 — Chemistry Physical Chemistry

Options

Did you get this right?

Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry

JEE Main 2026 — Chemistry Physical Chemistry

Options

Did you get this right?

Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry