ΔH=ΔU+ΔngRT For the reaction Δng=12−15=−3 ΔH−ΔU=−3×8.314×300=−7482 J mol−1
JEE Main 2012 — Chemistry Physical Chemistry
The difference between the reaction enthalpy change (ΔrH) and reaction internal energy change (ΔrU) for the reaction: 2C6H6(l)+15O2( g)⟶ at 300 K is (R=8.314 J mol−1 K−1)
Held on 12 May 2012 · Verified 6 Jul 2026.
0 J mol−1
2490 J mol−1
−2490 J mol−1
−7482 J mol−1
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