λ1=R(n121−n221) where R= Rydberg constant λ321=(41−91)=365⇒λ32=536 Similarly solving for λ31 and λ21 λ31=89 and λ21=34∴λ31λ32=6.4 and λ31λ21≃1.2
A doubly ionised Li atom is excited from its ground state(n=1) to n=3 state. The wavelengths of the spectral lines are given by λ32,λ31 and λ21. The ratio λ32/λ31 and λ21/λ31 are, respectively
Held on 12 May 2012 · Verified 6 Jul 2026.
8.1,0.67
8.1,1.2
6.4,1.2
6.4,0.67
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The given circuit works as : 
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