The distance traversed in the nth second is given by Sn=u+2a(2n−1).
For the first mass (m1=3.4 kg, u1=5 m/s):
104=5+2a1(2×5−1)
99=29a1⇒a1=22 m/s2
For the second mass (m2=2.5 kg, u2=12 m/s):
129=12+2a2(2×5−1)
117=29a2⇒a2=26 m/s2
Velocities of the masses after 10 s:
v1=u1+a1t=5+22×10=225 m/s
v2=u2+a2t=12+26×10=272 m/s
Momenta of the masses after 10 s:
p1=m1v1=3.4×225=765 kg m/s
p2=m2v2=2.5×272=680 kg m/s
Ratio of their momenta:
p2p1=680765=89
Comparing with 8x, we get x=9.
Answer: 9