From kinematics with s=0.81 m and t=9 s: a=2s/t2=0.02 m/s².
For the pulley system, applying Newton's second law to both masses and torque equation: (m1−m2)g−(m1+m2)a=Ia/R2.
Substituting values: 0.05×9.8−0.75×0.02=I×50 gives 0.49−0.015=50I.
Therefore I=9.5×10−3 kg·m²