Mass of each car m=103 kg.
Speed of car A, vA=72 km/h =72×185=20 m/s.
Speed of car B, vB=36 km/h =36×185=10 m/s.
Relative velocity of car A with respect to car B is vAB=vA−vB=20−10=10 m/s.
The cars are moving on parallel tracks separated by a perpendicular distance d=10 m.
The magnitude of angular momentum of car A with respect to car B is given by L=m×vAB×d.
Substituting the values: L=103×10×10=105 J.s.
Thus, the correct option is (2).