Given that the wires have equal cross-sectional area A and are under the same tension F, the elongation ΔL is given by:
ΔL=AYFL
Since the elongations in both wires are equal (ΔLA=ΔLB):
AYAFLA=AYBFLB
YALA=YBLB
LB=LA×YAYB
Substituting the given values LA=2.2 m and YBYA=1120:
LB=2.2×2011
LB=2024.2=1.21 m
Answer: 1.21