Using the work-energy theorem, the total work done by all forces equals the change in kinetic energy:
Wg+Wr=ΔK
mgh+Wr=21mv2−0
Substituting the given values (m=10−3 kg, g=10 m/s2, h=1000 m, v=5 m/s):
(10−3)(10)(1000)+Wr=21(10−3)(5)2
10+Wr=0.0125
Wr=0.0125−10=−9.9875 J
Wr≈−9.98 J
Answer: −9.98