The volume of a sphere in terms of its diameter D is given by V=6πD3
Taking the natural logarithm on both sides, we get lnV=ln(6π)+3lnD
Differentiating for small errors, we obtain VΔV=3DΔD
Multiplying by 100 to find the percentage error, VΔV×100=3(DΔD×100)
Given that the percentage error in the diameter is 2%, we have DΔD×100=2
Therefore, the percentage error in the volume is 3×2=6%
Answer: 6