Moment of inertia of the rod about axis AB passing through one of its ends:
Irod=3ML2=340×(3)2=340×9=120 kg⋅m2
Moment of inertia of the solid sphere about the same axis AB, using the parallel axis theorem I=Icm+md2:
Mass m=10 kg, radius R, distance from the centre of the sphere to axis AB is d=3 m.
Isphere=52mR2+md2=52(10)R2+10(3)2=4R2+90
Equating the two moments of inertia:
120=4R2+90
4R2=30
R2=215
R=215
Comparing with R=2α:
α=15
Hence, α=15.