The velocity components of the projectile are given by the derivatives of the position coordinates with respect to time.
vx=dtdx=dtd(24t)=24
vy=dtdy=dtd(43.6t−4.9t2)=43.6−9.8t
At t=2 s, the velocity components are:
vx=24
vy=43.6−9.8(2)=43.6−19.6=24
The angle θ made by the velocity vector with the horizontal is given by:
tanθ=vxvy=2424=1
θ=45∘
Answer: 45