The terminal velocity of an air bubble rising in a liquid is given by Stokes' law:
v=92ηr2ρg
Where:
r=2D=1 mm=10−3 m
ρ=2000 kg/m3
g=10 m/s2
v=0.5 cm/s=5×10−3 m/s
Rearranging the formula for the coefficient of viscosity η:
η=92vr2ρg
Substituting the given values:
η=92×5×10−3(10−3)2×2000×10
η=92×5×10−310−6×20000
η=92×5×10−32×10−2
η=92×4=98 Pa⋅s
To convert the viscosity from SI units (Pa⋅s) to CGS units (Poise), we multiply by 10:
η=98×10=980 Poise
η≈8.88 Poise
The closest given option is 8.8.
Answer: 8.8