By the law of conservation of mechanical energy, the total initial kinetic energy of the rolling object is converted into potential energy at the maximum height.
Total initial kinetic energy for an object rolling without slipping is given by:
K=Ktranslational+Krotational
K=21mv02+21Iω2
Substituting ω=Rv0 and I=mk2 (where k is the radius of gyration):
K=21mv02+21(mk2)(Rv0)2=21mv02(1+R2k2)
The potential energy at the maximum height h is:
U=mgh
Given h=10g7v02, we have:
U=mg(10g7v02)=107mv02
Equating kinetic and potential energy (K=U):
21mv02(1+R2k2)=107mv02
1+R2k2=1014=57
R2k2=57−1=52
The moment of inertia is I=52mR2, which corresponds to a solid sphere.
Answer: solid sphere