An air bubble rises through water with initial volume 2.9 cm³ at the bottom. Calculating pressures at both locations:
At bottom (5 m depth): P1=Patm+ρgh=105+103(10)(5)=1.5×105 Pa
At surface: P2=105 Pa
Initial temperature: T1=17°C=290 K, Final temperature: T2=27°C=300 K
Using ideal gas law: T1P1V1=T2P2V2
V2=V1×P2P1×T1T2=2.9×1051.5×105×290300
=2.9×1.5×2930=2.9×1.5×1.034≈4.5 cm³