From the equation of continuity:
A1v1=nA2v2
Here,
A1=30 cm2=30×10−4 m2
v1=50 cm/s=0.5 m/s
n=10
A2=15 mm2=15×10−6 m2
Substituting the given values:
(30×10−4)×0.5=10×(15×10−6)×v2
15×10−4=150×10−6×v2
15×10−4=1.5×10−4×v2
v2=1.5×10−415×10−4=10 m/s
Answer: 10 m/s