Linear momentum conservation: mv−2mv=23m⋅vcm, giving vcm=−23v.
Angular momentum about center of mass from the collision geometry:
Taking collision points 2 cm and 4 cm from the 12 cm bar's center at different positions, the angular momentum is L=m⋅v⋅r1+(−2m)⋅v⋅r2.
Calculating moment of inertia: I=121(20m)(0.12)2+m(0.02)2+2m(0.04)2=0.0276m
The angular frequency ω is obtained from ω=IL, giving ratio ωv=33.
