Using the parallel axis theorem for radius of gyration:
k2=kcm2+d2 where kcm is the radius of gyration about the center of mass and d is the distance from the center.
For a solid sphere:
Icenter=52MR2, so kcm2=52R2
With R=10 cm and d=15 cm:
k2=52(10)2+(15)2=40+225=265
Since k=n, we have n=265.