Horizontal velocity is constant: vx=ucos60°=2u.
When direction is 45° with horizontal and speed is 20 m/s:
vx=20cos45°=220.
2u=220⇒u=240=202 m/s.
JEE Main 2026 — Physics Mechanics
A projectile is thrown upward at an angle 60∘ with the horizontal. The speed of the projectile is 20 m/s when its direction of motion is 45∘ with the horizontal. The initial speed of the projectile is ____ m/s.
Held on 22 Jan 2026 · Verified 6 Jul 2026.
202
40
402
203
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