Using the equation of continuity:
AAvA=ABvB
(1.0×10−4)×0.1=(20×10−6)×vB
vB=2×10−510−5=0.5 m/s
Using Bernoulli's equation for a horizontal tube:
PA+21ρvA2=PB+21ρvB2
PA−PB=21ρ(vB2−vA2)
Substituting the given values:
PA−PB=21×600×(0.52−0.12)
PA−PB=300×(0.25−0.01)
PA−PB=300×0.24=72 Pa
Answer: 72