A chain of mass m hangs between two fixed points at the same level with inclination 30° at support points.
Consider equilibrium of one half of the chain (mass m/2):
Horizontal equilibrium: T0=T1cos(30°)=T1⋅23
Vertical equilibrium: T1sin(30°)=2mg
From vertical equation: T1⋅21=2mg, giving T1=mg
Substituting into horizontal equation: T0=mg⋅23=23mg