Volume of the cylindrical vessel, V=528 dm3=528000 cm3
Radius of the vessel, r=40 cm
Let the height of the vessel be H.
V=πr2H
528000=722×(40)2×H
H=22×1600528000×7=105 cm
The vessel is placed on a block of height equal to the vessel, so the height of the block is 105 cm.
Depth of the hole from the top water level, h=70 cm
Height of the hole from the ground, y=Height of block+(H−h)
y=105+(105−70)=140 cm
Velocity of efflux, v=2gh
Time of flight of water, t=g2y
Horizontal range, R=v×t=2gh×g2y=2hy
R=270×140=270×70×2=1402 cm
Answer: 1402