Given mass m=1 kg and velocity v=2x2.
According to the work-energy theorem, the work done by the net force is equal to the change in kinetic energy of the body.
W=ΔK=Kf−Ki
At x=0 m, initial velocity vi=2(0)2=0 m/s.
At x=5 m, final velocity vf=2(5)2=50 m/s.
Initial kinetic energy Ki=21mvi2=0 J.
Final kinetic energy Kf=21mvf2=21×1×(50)2=1250 J.
Work done W=1250−0=1250 J.
Answer: 1250