For motion without acceleration, net force = 0.
Component of weight along incline: mgsin(30°)=5×10×0.5=25 N (down).
Normal force: N=mgcos(30°)=50×23=253 N.
Friction force opposing downward motion:
f=μN=23×253=37.5 N (up).
For equilibrium along the incline, applying force F down the incline:
mgsinθ+F=f, so 25+F=37.5, giving F=12.5 N.