Using Bernoulli's theorem $\begin{aligned}
& P_1-P_2=\frac{1}{2} \rho v^2 \
& v \propto \sqrt{P_1-P_2}
\end{aligned}$
Water flows in a horizontal pipe whose one end is closed with a valve. The reading of the pressure gauge attached to the pipe is P1. The reading of the pressure gauge falls to P2 when the valve is opened. The speed of water flowing in the pipe is proportional to
Held on 23 Jan 2025 · Verified 6 Jul 2026.
P1−P2
(P1−P2)4
(P1−P2)2
P1−P2
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Work through every JEE Main Mechanics PYQ, year by year.