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Two slabs with square cross section of different materials (1,2) with equal sides (l) and thickness d_1 and d_2 such that d_2=2 ~d_1 and l gt d_2.…

JEE Main 2025 — Physics Mechanics

2025integerhard

Two slabs with square cross section of different materials (1,2)(1,2)(1,2) with equal sides (l)(l)(l) and thickness d1\mathrm{d}_1d1​ and d2\mathrm{d}_2d2​ such that d2=2 d1\mathrm{d}_2=2 \mathrm{~d}_1d2​=2 d1​ and l>d2l \gt \mathrm{d}_2l>d2​. Considering lower edges of these slabs are fixed to the floor, we apply equal shearing force on the narrow faces. The angle of deformation is θ2=2θ1\theta_2=2 \theta_1θ2​=2θ1​. If the shear moduli of material 1 is 4×109 N/m24 \times 10^9 \mathrm{~N} / \mathrm{m}^24×109 N/m2, then shear moduli of material 2 is x×109 N/m2\mathrm{x} \times 10^9 \mathrm{~N} / \mathrm{m}^2x×109 N/m2, where value of xxx is ________.

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Held on 4 Apr 2025 · Verified 6 Jul 2026.

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