HMax=2 g(usinθ)2(Hmax)2(Hmax)1=u2sin2(45+α)u2sin2(45−α)=(21cosα+21sinα)2(21cosα−21sinα)2=1+sin2α1−sin2α
Two projectiles are fired with same initial speed from same point on ground at angles of (45°-α ) and (45°+α ), respectively, with the horizontal…
JEE Main 2025 — Physics Mechanics
Two projectiles are fired with same initial speed from same point on ground at angles of (45∘−α) and (45∘+α), respectively, with the horizontal direction. The ratio of their maximum heights attained is :
Held on 29 Jan 2025 · Verified 6 Jul 2026.
Options
- A
1+tanα1−tanα
- B
1+sin2α1−sin2α
- C
1−sin2α1+sin2α
- D
1−sinα1+sinα
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