Since bulk modulus is given as $\begin{aligned}
& \mathrm{B}=\frac{-\Delta \mathrm{P}}{\left(\frac{\Delta \mathrm{V}}{\mathrm{V}}\right)} \
& 2.15 \times 10^9=\frac{-\Delta \mathrm{P}}{-\left(\frac{0.2}{100}\right)} \
& \Delta \mathrm{P}=2.15 \times 10^9 \times 2 \times 10^{-3} \
& =4.3 \times 10^6=43 \times 10^5 \mathrm{~N} / \mathrm{m}^2
\end{aligned}$