$\begin{aligned}
& W_1=s 4 \pi\left(\frac{R}{3}\right)^2 \times 27-4 \pi R^2 \cdot s \
& \Rightarrow W_1=4 \pi R^2 \cdot s(2)=10 \text { Joule }
\end{aligned}Now,W_2=s 4 \pi R^2(4-1)=4 \pi R^2 s \times 3\Rightarrow \quad W_2=3 \times \frac{10}{2}=15 \text { Joule }$