C′=ΔTΔQ=JK−1 S=mΔTΔQ=Jkg−1 K−1 L=mΔQ=Jkg−1ΔQ=LKAΔT⇒K=AΔTΔQ(L)=Jm−1 K−1 s−1
JEE Main 2025 — Physics Mechanics
Match List-I with List-II.
List-I(A) Heat capacity of body(B) Specific heat capacity of body(C) Latent heat(D) Thermal conductivityList-II(I) Jkg−1(II) JK−1(III) Jkg−1 K−1(IV) Jm−1 K−1 s−1
Choose the correct answer from the options given below :
Held on 2 Apr 2025 · Verified 6 Jul 2026.
(A)-(III), (B)-(I), (C)-(II), (D)-(IV)
(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
(A)-(II), (B)-(III), (C)-(I), (D)-(IV)
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